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Worked Examples · Example 36

Q.The production manager of a company plans to include 180 square centimetres of actual printed matter in each page of a book under production. Each page should have a 2.5 cm wide margin along the top and bottom and 2 cm wide margin along the sides. What are the most economical dimensions of each printed page?

Ladakh CbseNCERTSubjective· 5mImportance★★★★★
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With printed matter xy=180xy=180 and margins 22 cm (sides) and 2.52.5 cm (top/bottom), the page area A=200+5x+720xA=200+5x+\dfrac{720}{x} is minimised at x=12,x=12, giving a 16 cm×20 cm16\text{ cm}\times20\text{ cm} page.

Minimise the total page area AA subject to fixed printed area. Set A′(x)=0A'(x)=0 and verify A′′(x)>0A''(x)>0 for a minimum.

  1. Name the printed region: let the printed matter have width xx cm and height yy cm, with xy=180⇒y=180x.xy=180\Rightarrow y=\dfrac{180}{x}.
  2. Add margins to get page size: side margins 22 cm each add 44 cm to width; top/bottom margins 2.52.5 cm each add 55 cm to height. So page width =x+4=x+4 and page height =y+5.=y+5.
  3. Page area: A=(x+4)(y+5)=(x+4) ⁣(180x+5)=180+5x+720x+20=200+5x+720x.A=(x+4)(y+5)=(x+4)\!\left(\dfrac{180}{x}+5\right)=180+5x+\dfrac{720}{x}+20=200+5x+\dfrac{720}{x}.
  4. Differentiate: A′(x)=5−720x2.A'(x)=5-\dfrac{720}{x^2}.
  5. Critical point: A′(x)=0⇒5=720x2⇒x2=144⇒x=12A'(x)=0\Rightarrow 5=\dfrac{720}{x^2}\Rightarrow x^2=144\Rightarrow x=12 (taking the positive value). …

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