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Exercise 7.1 · Q6

Q.If you need ₹20,000 for your daughter's education, how much must you set aside each quarter for 10 years to accumulate this amount at the rate of 6% compounded quarterly?

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This is a future value of an ordinary annuity problem. You need to find the quarterly payment that grows to ₹20,000 in 10 years at 6% compounded quarterly. The required quarterly deposit is approximately ₹367.50.

The core idea here is that you are making regular, equal deposits (an annuity) into an account that earns compound interest. Each deposit grows for a different length of time, and the sum of all these future values must equal your target of ₹20,000.

We use the future value of an ordinary annuity formula because payments are made at the end of each quarter. The formula is:

FV=P×(1+r)n−1rFV = P \times \frac{(1 + r)^n - 1}{r}

Where:

  • FVFV = future value (₹20,000)
  • PP = periodic payment (what we need to find)
  • rr = interest rate per period
  • nn = total number of periods

Let's break this down step by step.

  1. Identify the variables from the problem.

    • Target amount: FV=₹20,000FV = ₹20,000
    • Annual interest rate: 6% = 0.06
    • Compounding frequency: quarterly (4 times per year)
    • Time: 10 years
  2. Calculate the interest rate per quarter.

    Since interest is compounded quarterly, we divide the annual rate by 4:

r=0.064=0.015 (or 1.5% per quarter)r = \frac{0.06}{4} = 0.015 \text{ (or 1.5\% per quarter)}

  1. Calculate the total number of quarters. In 10 years, with 4 quarters per year:

n=10×4=40 quartersn = 10 \times 4 = 40 \text{ quarters}

  1. Plug into the annuity formula and solve for PP. We have:

20,000=P×(1+0.015)40−10.01520,000 = P \times \frac{(1 + 0.015)^{40} - 1}{0.015}

First, compute (1.015)40(1.015)^{40}. This is the growth factor for one deposit over 40 quarters. Using a calculator:

(1.015)40≈1.814018(1.015)^{40} \approx 1.814018

Now compute the numerator of the fraction:

(1.015)40−1≈1.814018−1=0.814018(1.015)^{40} - 1 \approx 1.814018 - 1 = 0.814018

Divide by r=0.015r = 0.015:

0.8140180.015≈54.2679\frac{0.814018}{0.015} \approx 54.2679

So the equation becomes:

20,000=P×54.267920,000 = P \times 54.2679

Finally, solve for PP:

P=20,00054.2679≈368.50P = \frac{20,000}{54.2679} \approx 368.50

Watch out

A common mistake is to use the annual rate directly in the formula without dividing by the number of compounding periods per year. Always match the rate and the number of periods to the same time unit (here, quarters). …

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