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NCERT Exemplar · Q58

Q.Match each rate/concentration plot in Column I with the reaction order in Column II. More than one entry in Column I may correspond to the same entry in Column II.
Column I:

(i) A plot of reaction rate (vertical axis) against concentration (horizontal axis) that is a straight line passing through the origin (rate directly proportional to concentration).
(ii) A plot of reaction rate against concentration that is a horizontal line (rate independent of concentration).
(iii) A plot of concentration (vertical axis) against time that is a straight line decreasing steadily with time.
(iv) A plot of log⁡(concentration)\log(\text{concentration}) against time that is a straight line decreasing steadily with time.
Column II:
(a) First order
(b) Zero order
Ladakh CbseShort· 2mImportance★★★★★
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A rate proportional to concentration (line through the origin) and a linear log⁡(conc)\log(\text{conc})-time plot are first order; a rate independent of concentration (horizontal line) and a linear concentration-time plot are zero order. So (i) to (a), (ii) to (b), (iii) to (b), (iv) to (a).

Reasoning

  • (i) Rate vs concentration is a straight line through the origin: rate ∝\propto [conc], i.e. rate =k[A]1=k[\text{A}]^1 - first order (a).
  • (ii) Rate vs concentration is a horizontal line: rate is independent of concentration, rate =k=k - zero order (b). …

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