Q.Find the position vector of a point R which divides the line joining two points P and Q whose position vectors are and externally in the ratio . Also, show that P is the mid point of the line segment RQ.
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Start your 14-day free trial to unlock the full solution →Using the external section formula, the position vector of R is found to be . Substituting into the midpoint condition confirms that P is exactly the midpoint of RQ.
Concept and Intuition
The section formula is the backbone of this problem. When a point divides a line segment in a given ratio, we have two distinct cases:
- Internal division: The point lies between the two endpoints.
- External division: The point lies beyond one of the endpoints, on the line extended.
For external division, the formula looks almost like the internal one — but with a crucial sign change in the denominator. Why? Because when a point divides a segment externally, the distances are measured in opposite directions along the line, so one ratio component effectively becomes negative.
If point R divides the line joining P (position vector ) and Q (position vector ) externally in the ratio , then:
Notice the minus signs — this is the external section formula.
The second part of the problem asks us to show that P is the midpoint of RQ. This is a verification: once we have , we check whether .
Step-by-Step Solution
1. Identify the given vectors and ratio
We have:
- Position vector of P:
- Position vector of Q:
- Ratio: externally, with R dividing PQ. So , .
A common mistake is to swap P and Q in the formula. Read carefully: "divides the line joining P and Q" — so P comes first, Q second. In the external formula, the point corresponding to the first term in the numerator is Q (the second endpoint), not P. Always double-check the order.
2. Apply the external section formula
Using :
3. Simplify the numerator
First, expand:
4. Divide by the denominator
Denominator is . So:
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