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Worked Examples · Example 3

Q.Find the LCM of 5!,6!5!, 6! and 7!7!

Lakshadweep CbseNCERTSubjective· 2mImportance★★★★★est
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✓ Free question

When one number is a multiple of another, their LCM is simply the larger one; chain this fact through 5!∣6!∣7!5!\mid 6!\mid 7!.

n!=n×(n−1)!n! = n\times(n-1)!, so (n+1)!(n+1)! is always an integer multiple of n!n!. If a∣ba \mid b (a divides b), then LCM(a,b)=b\mathrm{LCM}(a,b) = b.

  1. 5!=1205! = 120.
  2. 6!=6×5!=6×120=7206! = 6\times5! = 6\times120 = 720, so 5!∣6!5! \mid 6!.
  3. 7!=7×6!=7×720=50407! = 7\times6! = 7\times720 = 5040, so 6!∣7!6! \mid 7! (and hence 5!∣7!5!\mid7! too).
  4. Since 5!5! divides 6!6! and 6!6! divides 7!7!, the least common multiple of all three is the largest of them, 7!7!.
  5. LCM(5!,6!,7!)=7!=5040\mathrm{LCM}(5!,6!,7!) = 7! = 5040.
✓Final answer

LCM(5!,6!,7!)=5040\mathrm{LCM}(5!, 6!, 7!) = 5040

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