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Exercise 12.1 · Q9

Q.lim⁡x→0ax+bcx+1\lim_{x\to 0}\dfrac{ax + b}{cx + 1}

Lakshadweep CbseNCERTSubjective· 2mImportance★★★★★est
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The denominator cx+1cx+1 does not vanish at x=0x=0 (it equals 11), so there is no indeterminate form — direct substitution gives the limit bb.

Why direct substitution works here

A rational function P(x)Q(x)\dfrac{P(x)}{Q(x)} is continuous at every point where its denominator is non-zero. When the denominator does not vanish at the target point, we may simply substitute the value.

Step 1 — Check the denominator at x=0x=0.

cx+1∣x=0=c(0)+1=1≠0.cx+1\Big|_{x=0}=c(0)+1=1\neq 0. …

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