Q.Find the mean and variance for the following data: 6, 7, 10, 12, 13, 4, 8, 12

Variance and Standard Deviation of Data

For a data set these measure spread about the mean. For ungrouped data

$x_1,\dots,x_n$ with mean $\bar x$,

$\sigma^2=\dfrac1n\sum_{i=1}^n (x_i-\bar x)^2=\dfrac{\sum x_i^2}{n}-\bar x^2,$

and the standard deviation is $\sigma=\sqrt{\sigma^2}$. For a frequency distribution with values $x_i$ (class midpoints for grouped data) and frequencies

$f_i$, $N=\sum f_i$,

$\sigma^2=\dfrac{\sum f_i x_i^2}{N}-\Big(\dfrac{\sum f_i x_i}{N}\Big)^2.$

The coefficient of variation $\mathrm{CV}=\dfrac{\sigma}{\bar x}\times100$ compares

relative spread. Variance is unchanged by a shift of origin and scales as

$a^2$ under $x\mapsto ax+b$. For two groups combined, the pooled variance uses the

group means $\bar x_1,\bar x_2$ and the overall mean $\bar x$:

$\sigma^2=\dfrac{n_1(\sigma_1^2+d_1^2)+n_2(\sigma_2^2+d_2^2)}{n_1+n_2}$ with

$d_j=\bar x_j-\bar x$. These formulas cover ungrouped, grouped and combined data.

Variance and standard deviation of both ungrouped and grouped data are part of the NCERT/CBSE Class 11 Mathematics "Statistics" chapter, matching "variance and standard deviation formula class 11 maths" searches. These measures of dispersion are also frequently tested in JEE Main and CET quantitative-aptitude sections.