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Worked Examples · Example 10

Q.Let A=[35−46]A = \begin{bmatrix} 3 & 5 \\ -4 & 6 \end{bmatrix} and B=[−921−7]B = \begin{bmatrix} -9 & 2 \\ 1 & -7 \end{bmatrix}, find ABAB and BABA.

Lakshadweep CbseNCERTSubjective· 3mImportance★★★★★
13% · 10/80 Questions
✓ Free question

Multiply row-by-column for both orders; the products differ, showing matrix multiplication is not commutative.

For 2×22\times 2 matrices, (PQ)ij=∑kpikqkj(PQ)_{ij}=\sum_{k}p_{ik}q_{kj} — each entry is (row ii of the first)⋅\cdot(column jj of the second).

  1. Compute ABAB with A=[35−46]A=\begin{bmatrix} 3 & 5 \\ -4 & 6 \end{bmatrix}, B=[−921−7]B=\begin{bmatrix} -9 & 2 \\ 1 & -7 \end{bmatrix}:
    • (1,1): 3(−9)+5(1)=−27+5=−22(1,1):\ 3(-9)+5(1)=-27+5=-22,
    • (1,2): 3(2)+5(−7)=6−35=−29(1,2):\ 3(2)+5(-7)=6-35=-29,
    • (2,1): −4(−9)+6(1)=36+6=42(2,1):\ -4(-9)+6(1)=36+6=42,
    • (2,2): −4(2)+6(−7)=−8−42=−50(2,2):\ -4(2)+6(-7)=-8-42=-50.

AB=[−22−2942−50].AB=\begin{bmatrix} -22 & -29 \\ 42 & -50 \end{bmatrix}.

  1. Compute BABA:
    • (1,1): −9(3)+2(−4)=−27−8=−35(1,1):\ -9(3)+2(-4)=-27-8=-35,
    • (1,2): −9(5)+2(6)=−45+12=−33(1,2):\ -9(5)+2(6)=-45+12=-33,
    • (2,1): 1(3)+(−7)(−4)=3+28=31(2,1):\ 1(3)+(-7)(-4)=3+28=31,
    • (2,2): 1(5)+(−7)(6)=5−42=−37(2,2):\ 1(5)+(-7)(6)=5-42=-37.

BA=[−35−3331−37].BA=\begin{bmatrix} -35 & -33 \\ 31 & -37 \end{bmatrix}.

  1. Compare: AB≠BAAB\neq BA, confirming matrix multiplication is generally non-commutative.
✓Final answer

AB=[−22−2942−50],BA=[−35−3331−37]AB=\begin{bmatrix} -22 & -29 \\ 42 & -50 \end{bmatrix},\quad BA=\begin{bmatrix} -35 & -33 \\ 31 & -37 \end{bmatrix}, and AB≠BAAB\neq BA.

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