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Worked Examples · Example 14

Q.Ms. Rajni deposited ₹10,000 in a bank that pays 4% interest compounded continuously.

a) How much amount will she get after 10 years?
b) How long it will take the money to double?
Lakshadweep CbseNCERTSubjective· 3mImportance★★★★★est
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Continuous compounding A=PertA=Pe^{rt}: after 10 yr, A≈₹14,918A\approx ₹14{,}918; the money doubles in ≈17.33\approx17.33 years.

A=PertA=Pe^{rt}, where PP = principal, rr = annual rate (decimal), tt = time (years), AA = amount. (This solves dAdt=rA\dfrac{dA}{dt}=rA.)

Given: P=₹10,000P=₹10{,}000, r=4%=0.04r=4\%=0.04.

(a) Amount after 10 years:

  1. A=Pert=10,000 e0.04×10=10,000 e0.4A=Pe^{rt}=10{,}000\,e^{0.04\times10}=10{,}000\,e^{0.4}.
  2. e0.4≈1.4918e^{0.4}\approx1.4918.
  3. A≈10,000×1.4918=₹14,918A\approx10{,}000\times1.4918=₹14{,}918.

(b) Time to double (A=2PA=2P): …

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