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Exercises · 9.14

Q.In the alkane H3C–CH2–C(CH3)2–CH2–CH(CH3)2, identify 1°, 2°, 3° carbon atoms and give the number of H atoms bonded to each one of these.

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Classifying each carbon by how many other carbons it is bonded to, the alkane H3C−CH2−C(CH3)2−CH2−CH(CH3)2H_3C-CH_2-C(CH_3)_2-CH_2-CH(CH_3)_2 has 5 primary (1 deg) carbons (3 H each), 2 secondary (2 deg) carbons (2 H each), 1 tertiary (3 deg) carbon (1 H) and 1 quaternary (4 deg) carbon (0 H).

Rule

A carbon is primary / secondary / tertiary / quaternary according to whether it is bonded to 1 / 2 / 3 / 4 other carbons, and its hydrogen count is 4−(number of C neighbours)4 - (\text{number of C neighbours}).

The molecule (C9H20C_9H_{20})

H3C1−C2H2−C3(CH3)2−C4H2−C5H(CH3)2H_3\overset{1}{C}-\overset{2}{C}H_2-\overset{3}{C}(CH_3)_2-\overset{4}{C}H_2-\overset{5}{C}H(CH_3)_2

Nine carbons in all: backbone C1 to C5, two methyls on C3, two methyls on C5.

CarbonC neighboursTypeH atoms
C1 (terminal CH3CH_3)1primary3
C2 (CH2CH_2)2secondary2
C3 (central C)4quaternary0
two CH3CH_3 on C31 eachprimary3 each
C4 (CH2CH_2)2secondary2

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