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Q.The Vividh Bharati Station of All India Radio, Delhi, broadcasts at a frequency of 1.368 kHz (kilo hertz). Calculate the wavelength of the electromagnetic radiation emitted by the transmitter. Which part of the electromagnetic spectrum does it belong to? OR The wavelength range of the visible spectrum extends from violet (400 nm) to red (750 nm). Express these wavelengths in frequencies (Hz). (1 nm = 10^-9 m)

Madhya Pradesh MpbseMP Board Higher Secondary (Class 11) 2023Subjective· 5mImportance★★★★★
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Using lambda = c/nu with nu = 1.368 x 10^6 Hz gives a wavelength of about 219.3 m, placing the signal in the radio-wave region of the EM spectrum.

The relationship between the speed of light (c), frequency (nu), and wavelength (lambda) of an electromagnetic wave is:

c = nu x lambda, so lambda = c / nu

Given: frequency nu = 1.368 kHz = 1.368 x 10^3 x 10^3 Hz = 1.368 x 10^6 Hz

Speed of light, c = 3 x 10^8 m/s

lambda = c / nu = (3 x 10^8 m/s) / (1.368 x 10^6 /s)

lambda = (3 / 1.368) x 10^2 m

lambda = 2.193 x 10^2 m

lambda = 219.3 m (approximately)

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