Skip to content
Question of 90
Q.

Find the mean deviation about the mean for the given data:

x1030507090
f42428168

OR

Find the mean deviation about the median for the given data:

Class0-1010-2020-3030-4040-5050-60
Frequency67151642
Madhya Pradesh MpbseMP Board Higher Secondary (Class 11) 2022Subjective· 4mImportance★★★★★
0% · 0/90 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The mean deviation about the mean for the given data is 1616.

| xx | ff | fxfx | ∣x−xˉ∣|x-\bar x| | f∣x−xˉ∣f|x-\bar x| |

|---|---|---|---|---|

| 10 | 4 | 40 | 40 | 160 |

| 30 | 24 | 720 | 20 | 480 |

| 50 | 28 | 1400 | 0 | 0 |

| 70 | 16 | 1120 | 20 | 320 |

| 90 | 8 | 720 | 40 | 320 |

N=∑f=4+24+28+16+8=80N = \sum f = 4+24+28+16+8 = 80

∑fx=40+720+1400+1120+720=4000\sum fx = 40+720+1400+1120+720 = 4000

Mean xˉ=∑fxN=400080=50\bar x = \dfrac{\sum fx}{N} = \dfrac{4000}{80} = 50

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.