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Q.Find the mean deviation about the mean for the following data: Marks obtained: 10-20, 20-30, 30-40, 40-50, 50-60, 60-70, 70-80
Number of students: 2, 3, 8, 14, 8, 3, 2 OR Find the mean and variance of the following frequency distribution: Class: 0-10, 10-20, 20-30, 30-40, 40-50
Frequency: 5, 8, 15, 16, 6

Madhya Pradesh MpbseMP Board Higher Secondary (Class 11) 2025Subjective· 4mImportance★★★★★
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For the given frequency table, the mean is 4545 and the mean deviation about the mean is 1010.

Step 1 — Class midpoints (xix_i): 15, 25, 35, 45, 55, 65, 75 for the classes 10-20 through 70-80, with frequencies fif_i: 2, 3, 8, 14, 8, 3, 2 (total N=40N = 40).

Step 2 — Mean:

∑fixi=2(15)+3(25)+8(35)+14(45)+8(55)+3(65)+2(75)\sum f_ix_i = 2(15)+3(25)+8(35)+14(45)+8(55)+3(65)+2(75)

=30+75+280+630+440+195+150=1800= 30+75+280+630+440+195+150 = 1800.

xˉ=∑fixiN=180040=45\bar{x} = \dfrac{\sum f_ix_i}{N} = \dfrac{1800}{40} = 45.

Step 3 — Absolute deviations ∣xi−xˉ∣|x_i - \bar{x}|: 30, 20, 10, 0, 10, 20, 30.

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