NCERT Exemplar · Q40
Q.Two Daniell-type cells, Cell 'A' and Cell 'B', are connected to each other in opposition (their EMFs oppose). In each cell a zinc electrode dips in a Zn2+(aq) solution and a copper electrode dips in a Cu2+(aq) solution, the two half-cells being joined by a salt bridge. When two such cells are coupled in opposition, the cell of higher EMF discharges and drives the cell of lower EMF in reverse, so the lower-EMF cell is forced to behave as an electrolytic cell. Answer the following.
(i) Cell 'A' has and Cell 'B' has . Which of the two cells, 'A' or 'B', will act as an electrolytic cell, and which electrode reactions will occur in that cell?
(ii) If Cell 'A' has and Cell 'B' has , what will be the reactions at the anode and the cathode of the cell that is forced to act as the electrolytic cell?
Madhya Pradesh MpbseLong· 5mImportance★★★★★est
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Start your 14-day free trial to unlock the full solution →When two cells are joined in opposition, the one with the larger EMF acts as a galvanic cell (source) and forces the smaller-EMF cell to run backwards, i.e. as an electrolytic cell. Running a Daniell cell backwards reverses its normal reactions: the zinc electrode becomes the cathode (Zn2+ deposits as Zn) and the copper electrode becomes the anode (Cu dissolves as Cu2+).
Concept
A Daniell cell spontaneously (as a galvanic cell) undergoes:
- Anode (Zn): Zn → Zn2+ + 2e-
- Cathode (Cu): Cu2+ + 2e- → Cu
If an external source of higher EMF pushes current through it the opposite way, the cell is electrolysed and every electrode reaction reverses:
- Zn electrode becomes the cathode: Zn2+ + 2e- → Zn
- Cu electrode becomes the anode: Cu → Cu2+ + 2e-
(i) ,
- Compare the EMFs: .
- The stronger cell, A, works as a galvanic cell and supplies current; the weaker cell, B, is driven in reverse and therefore behaves as the electrolytic cell.
- Reactions in Cell B (reversed Daniell):
- Cathode (zinc electrode): Zn2+ + 2e- → Zn (reduction)
- Anode (copper electrode): Cu → Cu2+ + 2e- (oxidation)
(ii) , …
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