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Mathematics and Statistics · Ch 7 — Limits

Limits at Infinity

5

Limits at Infinity

Instead of xx approaching a finite number, we may ask what f(x)f(x) approaches as xx grows without bound — written lim⁡x→∞f(x)\displaystyle\lim_{x\to\infty} f(x) (and similarly x→−∞x\to-\infty). The single most useful fact is

lim⁡x→∞1xk=0for any k>0,\lim_{x\to\infty} \frac{1}{x^{k}} = 0 \quad\text{for any } k>0,

because a fixed number divided by an ever-larger denominator shrinks to 00.

The standard technique for a rational function p(x)q(x)\dfrac{p(x)}{q(x)} as x→∞x\to\infty: divide every term of the numerator and denominator by the highest power of xx present in the denominator, then send each 1xk\tfrac{1}{x^k} term to 00.

Illustration. lim⁡x→∞3x2+5x−12x2−x+4\displaystyle\lim_{x\to\infty}\frac{3x^2 + 5x - 1}{2x^2 - x + 4}. The highest power in the denominator is x2x^2; dividing every term by x2x^2:

3+5x−1x22−1x+4x2→ x→∞ 3+0−02−0+0=32.\frac{3 + \dfrac{5}{x} - \dfrac{1}{x^2}}{2 - \dfrac{1}{x} + \dfrac{4}{x^2}} \xrightarrow{\ x\to\infty\ } \frac{3 + 0 - 0}{2 - 0 + 0} = \frac{3}{2}.

The degree shortcut. For p(x)q(x)\dfrac{p(x)}{q(x)} with numerator degree mm and denominator degree nn:

  • if m<nm < n, the limit is 00;
  • if m=nm = n, the limit is the ratio of the leading coefficients;
  • if m>nm > n, the expression grows without bound (limit is ∞\infty or −∞-\infty).
Note

Divide by the Denominator's Highest Power, Not the Numerator's …

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lim⁡x→∞f(x)\lim_{x\to\infty}f(x) asks what f(x)f(x) approaches as xx grows without bound. Key fact: $\lim_{x\to\infty}\tfrac{ …

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For p(x)q(x)\tfrac{p(x)}{q(x)} as x→∞x\to\infty with degrees mm (num) and nn (den): limit is 00 if m<nm<n; the leading-coefficient ratio if $m= …