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Miscellaneous Exercise 1 (Subjective) · Q45

Q.In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.

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Step 1: Diameter =40=40 cm ⇒r=20\Rightarrow r=20 cm. Chord =20=20 cm.

Step 2: chord=2rsin⁡(θ2)⇒20=2(20)sin⁡(θ2)⇒sin⁡(θ2)=0.5⇒θ2=30°⇒θ=60°=π3\text{chord}=2r\sin\left(\frac{\theta}{2}\right) \Rightarrow 20=2(20)\sin\left(\frac{\theta}{2}\right) \Rightarrow \sin\left(\frac{\theta}{2}\right)=0.5 \Rightarrow \frac{\theta}{2}=30° \Rightarrow \theta=60°=\frac{\pi}{3} radian. …

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