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Exercise 1.2 · Q77

Q.Find the value of x3−x2+x+46x^3-x^2+x+46, if x=2+3ix = 2+3i.

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x=2+3ix=2+3i. x2=(2+3i)2=4+12i+9i2=4+12i−9=−5+12ix^2=(2+3i)^2=4+12i+9i^2=4+12i-9=-5+12i. x3=x2cdotx=(−5+12i)(2+3i)=−10−15i+24i+36i2=−10+9i−36=−46+9ix^3=x^2\\cdot x=(-5+12i)(2+3i)=-10-15i+24i+36i^2=-10+9i-36=-46+9i. So $x^3-x^2+x+46=(-46+9i)-(-5 …

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