Exercise 1.3 · Q107
Q.Convert the complex number in the polar form.
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Start your 14-day free trial to unlock the full solution →Numerator has modulus and (Quadrant II) argument , so . The denominator already has modulus and argument . Dividing two polar-form numbers divides their moduli and subtracts their arguments: $z=\dfrac{\sqrt2}{1}\left[\cos\left(\dfrac{3\pi}{4}-\dfrac{\pi}{3}\right)+i\sin\left(\dfrac{3\pi}{4}-\dfrac{\pi}{3}\right)\right]=\sqrt2\left(\co …
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