Properties of Summation: (i) ∑r=1nktr=k∑r=1ntr for a nonzero constant k; (ii) ∑r=1n(ar+br)=∑r=1nar+∑r=1nbr; (iii) ∑r=1n1=n; (iv) ∑r=1nk=kn for a nonzero constant k (a restatement of (i) and (iii) together).
Result 1: the sum of the first n natural numbers is ∑r=1nr=2n(n+1).
Result 2: the sum of the squares of the first n natural numbers is ∑r=1nr2=6n(n+1)(2n+1).
Result 3: the sum of the cubes of the first n natural numbers is ∑r=1nr3=[2n(n+1)]2 (these three results can be formally proved using Mathematical Induction, covered later in the book).
Worked Example 1: evaluate ∑r=1n(8r−7). =8∑r−7∑1=8⋅2n(n+1)−7n=4n2+4n−7n=4n2−3n.
Worked Example 2: find 32+42+52+⋯+292. =∑r=129r2−∑r=12r2=629⋅30⋅59−62⋅3⋅5=(29×5×59)−5=5(29×59−1)=5(1710)=8550.
Worked Example 3: find 1002−992+982−972+⋯+22−12. Grouping the even-indexed and odd-indexed squares separately: =∑r=150(2r)2−∑r=150(2r−1)2=∑r=150(4r−1)=4⋅250⋅51−50=5100−50=5050. …