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EXERCISE 2.4 · Q68

Q.Find the nnth term and hence find the 8th term of the H.P.: 14,16,18,110,…\dfrac14, \dfrac16, \dfrac18, \dfrac1{10}, \ldots

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Reciprocals 4,6,8,10,…4,6,8,10,\ldots: A.P. with a=4,d=2a=4, d=2, so tn(A.P.)=4+(n−1)2=2n+2t_n(\text{A.P.})=4+(n-1)2=2n+2. Hence H.P. tn=12n+2t_n=\dfrac1{2n+2}. $t_8=\dfrac1 …

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