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Miscellaneous Exercise 5 (II) · Q107

Q.If A = {1, 2, 3}, B = {4, 5, 6} check if the following is a relation from A to B. Also write its domain and range: R4 = {(4, 2), (2, 6), (5, 1), (2, 4)}.

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Check each pair against A×BA\times B where A={1,2,3}, B={4,5,6}: (4,2)(4,2) has first component 4, but 4∉A4\notin A — invalid. (5,1)(5,1) has first component 5 (∉A\notin A) and second component 1 (∉B\notin B) — invalid. Since not every pair of R4R_4 lies in A×BA\times B (in fact most don't), R4⊈A×BR_4 \not\subseteq A\times B, so R4R_4 is NOT a relation from A to B (even though the pair (2,6) and (2,4) individually would qualify, the whole set R4 must be …

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