Physics · Ch 5 — Gravitation
Acceleration due to Gravity
Acceleration due to Gravity
Section 5.3 gave the gravitational force between two point masses as . Since the Earth is, to a very good approximation, a uniform sphere, its entire mass M can (by the shell theorem of section 5.3) be treated as though concentrated at its centre when computing the force on an external point object of mass m at distance r from that centre: .
If no other force acts on the object, Newton's second law lets this force be converted directly into an acceleration: . This acceleration -- towards the centre of the Earth -- is called the acceleration due to gravity, denoted g. Crucially, the object's OWN mass m cancelled out of the expression entirely: depends only on the Earth's mass M and the distance r, never on the mass of the falling object itself. This is exactly the property Galileo discovered experimentally: bodies of different mass, dropped from the same height, fall with identical acceleration.
When the object is close to the Earth's surface, (the Earth's radius), giving the familiar surface value m/s^2 -- treated as effectively constant for objects near the surface, since the small variation in their distance from the Earth's centre over ordinary heights (a building, a hill) is negligible compared to R itself. …
Worked out. Given m/s^2, m and N m^2/kg^2, rearranging to gives kg, matching the accepted mass of the Earth -- demonstrating that the same law used for orbits and falling apples can be inverted to 'weigh' the entire planet …
Worked out. Given the Moon's mass is 1/80 that of the Earth () and its diameter (hence radius) is 1/4 that of the Earth (), the ratio , so m/s^2 -- the well-known result that lunar gravity is roughly one-sixth (here approximated as one-fifth) of Earth's. …
Worked out. Given and , using , so m/s^2 -- illustrating that a much more massive planet can still have very weak surface gravity if its radius is large enough, since g falls off with the SQUARE of radius but rises only linearly with mass. …