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Physics · Ch 6 — Mechanical Properties of Solids

Bulk modulus (K)

6.5.2

Bulk modulus (K)

Bulk modulus is the modulus of elasticity associated with a change in the volume of an object under an applied deforming force — hence it is also called the elasticity of volume. Unlike Young's modulus and the modulus of rigidity (both of which apply only to solids), bulk modulus is a property that solids, liquids and gases all possess, since all three states of matter have a definite volume that can be compressed.

Picture a rubber sphere fully immersed in a liquid, so that it is compressed uniformly from every side (exactly the volume-stress geometry of Fig. 6.2). Suppose the applied compressive force produces a small change in pressure dPdP on the sphere, and a corresponding small change in its volume dVdV, starting from an original volume VV. The volume strain produced is defined as

Volume strain=−dVV\text{Volume strain} = -\dfrac{dV}{V}

The negative sign here is not arbitrary — it explicitly records that an increase in pressure (dPdP positive) produces a decrease in volume (dVdV negative), so the ratio dV/VdV/V on its own would be negative; the minus sign in front makes the volume strain itself come out as a positive quantity, equal in magnitude to ∣dV∣/V|dV|/V.

Bulk modulus KK is then defined as the ratio of volume stress to volume strain:

K=dP−dV/V=−VdPdVK = \dfrac{dP}{-dV/V} = -V\dfrac{dP}{dV}

Its SI unit is N/m2\text{N/m}^2, and its dimensional formula is [L−1M1T−2][L^{-1}M^1T^{-2}], the same as for stress. Table 6.2 lists bulk moduli for common materials — a large bulk modulus (like steel or gold) means a material strongly resists having its volume squeezed down, while a small bulk modulus means the opposite.

The reciprocal of the bulk modulus is called the compressibility of a material:

Compressibility=1K\text{Compressibility} = \dfrac{1}{K} …

Table 6.2Bulk modulus of some familiar materials, showing how strongly each resists volume change

Material | Bulk modulus K ×10^10 Pa (N/m2)

Lead | 4.1

Brass | 6.0

Glass (crown) | 6.0

Aluminium | 7.5

Silver | 10.0

Copper | 14.0 …

Misc Ex.6.3Change in pressure on a compressed metal cube

Worked out. Worked example finding the change in pressure dP applied to a metal cube of side 1 m (so its original volume V = 1 m³), whose volume changes by dV = 1.5×10^-5 m³ under a normal force applied uniformly over its whole surface, given that the bulk modulus of the metal is K = 6.6×10^10 N/m². The method rearranges K = -V(dP/dV) to dP = K(dV/V), substitutes the given values directly, and obtains dP = 9.9×10^5 N/m² — a direct application of the bulk modulus formula to the uniform-all-round compression setup shown in Fig. 6.2, and a numerical illustration of why the bulk modulus of water (2.18×10^8 Pa) and its very high compressibility make wate …