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Numerical · Q45

Q.A telephone wire 125 m long and 1 mm in radius is stretched to a length of 125.25 m when a force of 800 N is applied. What is the value of Young's modulus for the material of the wire?

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Step 1. Given: L=125L = 125 m, radius r=1 mm=1×10−3r = 1\ \text{mm} = 1\times10^{-3} m, new length =125.25= 125.25 m so ΔL=0.25\Delta L = 0.25 m, F=800F = 800 N.

Step 2. Cross-sectional area: A=πr2=π(1×10−3)2=3.1416×10−6 m2A = \pi r^2 = \pi (1\times10^{-3})^2 = 3.1416\times10^{-6}\ \text{m}^2. …

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