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Worked Examples · Example 5

Q.The demand function for a commodity is p=25−2xp = 25 - 2x, where pp is the price per unit (in ₹) when xx units are demanded. Find the total revenue and the marginal revenue, and evaluate the marginal revenue at x=3x = 3.

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Total revenue. Revenue is price per unit times number of units:

R(x)=p⋅x=(25−2x) x=25x−2x2.R(x) = p \cdot x = (25 - 2x)\,x = 25x - 2x^2.

Marginal revenue. Differentiate RR with respect to xx:

MR=dRdx=25−4x.\text{MR} = \frac{dR}{dx} = 25 - 4x.

At x=3x = 3:

MR(3)=25−4(3)=25−12=13.\text{MR}(3) = 25 - 4(3) = 25 - 12 = 13.

So the marginal revenue is ₹13 — the approximate extra revenue from selling the 4th unit.

Dual check against the actual increment R(4)−R(3)R(4) - R(3):

R(4)=25(4)−2(16)=100−32=68,R(3)=25(3)−2(9)=75−18=57,R(4) = 25(4) - 2(16) = 100 - 32 = 68, \qquad R(3) = 25(3) - 2(9) = 75 - 18 = 57, …

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