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Question 33 of 35

Q.The true discount on a sum is 38\frac{3}{8} of the sum due at 12% p.a. Find the period of the bill.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026Subjective· 3mImportance★★★★★
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T.D.A=nr100+nr=38\dfrac{\text{T.D.}}{A}=\dfrac{nr}{100+nr}=\dfrac38 gives 5nr=300⇒nr=605nr=300\Rightarrow nr=60; with r=12r=12, n=5n=5 years.

Let the sum due (face value) be AA, the rate r=12%r = 12\% p.a. and the period nn years.

True discount formula:

T.D.=A⋅n⋅r100+nr.\text{T.D.} = \frac{A\cdot n\cdot r}{100 + nr}.

Given: the true discount is 38\frac{3}{8} of the sum due, i.e. T.D.=38A\text{T.D.} = \dfrac{3}{8}A.

So

A nr100+nr=38A  ⇒  nr100+nr=38.\frac{A\,nr}{100 + nr} = \frac{3}{8}A \;\Rightarrow\; \frac{nr}{100 + nr} = \frac{3}{8}.

Cross-multiplying:

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