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Worked Examples · Example 4

Q.Using the same data as the previous example (∑p0q0=170, ∑p1q0=216, ∑p0q1=190, ∑p1q1=237\sum p_0q_0=170,\ \sum p_1q_0=216,\ \sum p_0q_1=190,\ \sum p_1q_1=237), compute Fisher's ideal price index number, and state why it is called 'ideal'.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Fisher's ideal index is the geometric mean of Laspeyre's and Paasche's indices:

P01F=P01L×P01P=∑p1q0∑p0q0×∑p1q1∑p0q1×100.P_{01}^{F} = \sqrt{P_{01}^{L}\times P_{01}^{P}} = \sqrt{\frac{\sum p_1 q_0}{\sum p_0 q_0}\times\frac{\sum p_1 q_1}{\sum p_0 q_1}}\times100.

Substituting the four totals,

P01F=216170×237190×100=216×237170×190×100=5119232300×100=1.584892×100.P_{01}^{F} = \sqrt{\frac{216}{170}\times\frac{237}{190}}\times100 = \sqrt{\frac{216\times237}{170\times190}}\times100 = \sqrt{\frac{51192}{32300}}\times100 = \sqrt{1.584892}\times100.

Now 1.584892=1.25893\sqrt{1.584892} = 1.25893, so P01F=125.89P_{01}^{F} = 125.89.

Independent check (from the two indices). From Example 3, L=127.06L = 127.06 and P=124.74P = 124.74; their geometric mean is 127.06×124.74=15849.06=125.89\sqrt{127.06\times124.74} = \sqrt{15849.06} = 125.89 — the same value. …

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