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Question 25 of 25

Q.Find the present value of an annuity immediate of ₹18,000 per annum, for 3 years at 9% per annum, compounded annually.
[Given: (1.09)−3=0.7722(1.09)^{-3} = 0.7722]

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2020Subjective· 3mImportance★★★★★
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P=Ci[1−(1+i)−n]=180000.09[1−0.7722]=200000×0.2278=₹45,560P = \frac{C}{i}[1 - (1+i)^{-n}] = \frac{18000}{0.09}[1 - 0.7722] = 200000 \times 0.2278 = ₹45{,}560.

For an annuity immediate the present value is

P=Ci[1−(1+i)−n],P = \frac{C}{i}\Big[1 - (1 + i)^{-n}\Big],

with C=18,000C = 18{,}000, i=9%=0.09i = 9\% = 0.09, n=3n = 3 and (1.09)−3=0.7722(1.09)^{-3} = 0.7722.

Compute: …

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