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Question 24 of 28

Q.If the corner points of the feasible region are (0,10)(0, 10), (2,2)(2, 2) and (4,0)(4, 0) then the point of minimum z=3x+2yz = 3x + 2y is ______.

(a) (2,2)(2, 2)
(b) (0,10)(0, 10)
(c) (4,0)(4, 0)
(d) (2,4)(2, 4)
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026MCQ· 1mImportance★★★★★
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Evaluating z=3x+2yz = 3x + 2y at the corner points (0,10)(0,10), (2,2)(2,2) and (4,0)(4,0) gives 2020, 1010 and 1212; the least is 1010 at (2,2)(2,2).

By the corner-point (vertex) method, the optimum of a linear objective over a feasible polygon occurs at one of its corner points. Compute z=3x+2yz = 3x + 2y at each:

z(0,10)=3(0)+2(10)=20z(0,10) = 3(0) + 2(10) = 20

z(2,2)=3(2)+2(2)=6+4=10z(2,2) = 3(2) + 2(2) = 6 + 4 = 10 …

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