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Exercise 2.2 · Q18

Q.Find the inverse of the following matrix by the adjoint method. [2−243]\begin{bmatrix} 2 & -2 \\ 4 & 3 \end{bmatrix}

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Step 1: A=[2−243]A=\begin{bmatrix} 2 & -2 \\ 4 & 3 \end{bmatrix}. A11=3, A12=−4, A21=2, A22=2A_{11}=3,\ A_{12}=-4,\ A_{21}=2,\ A_{22}=2.

Step 2: Cofactor matrix [3−422]\begin{bmatrix}3&-4\\2&2\end{bmatrix}, so adj A=[32−42]\text{adj}\,A=\begin{bmatrix}3&2\\-4&2\end{bmatrix}.

Step 3: ∣A∣=2(3)−4(−2)=6+8=14≠0|A|=2(3)-4(-2)=6+8=14\neq0. …

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