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Worked Examples · Example 9

Q.Calculate the standard deviation of the values 5, 10, 25, 30 and 50 by the assumed mean method, taking the assumed mean as 25.

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With A=25A = 25: ∑d=−5\sum d = -5, ∑d2=1275\sum d^2 = 1275, so σ=255−1=254=15.937\sigma = \sqrt{255 - 1} = \sqrt{254} = 15.937.

Step 1 — Deviations from the assumed mean A=25A = 25 (with d=X−Ad = X - A).

Xd = X − 25d²
5−20400
10−15225
2500
30+525
50+25625
Total−51275

Step 2 — Standard deviation. …

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