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Problems · Problem 4.1

Q.Write the Lewis dot structure of the CO molecule.

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The Lewis dot structure of CO shows a triple bond between C and O, with one lone pair on carbon and one lone pair on oxygen. This satisfies the octet rule for both atoms and accounts for the molecule’s 10 valence electrons.

Why Lewis structures work — and why CO is special

Lewis dot structures are built on a simple idea: atoms share or transfer electrons so that each atom (except hydrogen) ends up with 8 electrons around it — the octet rule. You count total valence electrons, arrange them as bonds and lone pairs, then check if every atom is satisfied.

CO looks straightforward — just two atoms — but it’s a classic trap. Carbon has 4 valence electrons, oxygen has 6, total = 10. If you try a double bond (C=O), carbon ends up with only 6 electrons. That’s not enough. So CO must use a triple bond, which is unusual for a molecule with only two different elements. Let’s build it step by step.

Step-by-step construction

1. Count valence electrons.

Carbon (Group 14): 4 electrons.

Oxygen (Group 16): 6 electrons.

Total = 4+6=104 + 6 = 10 valence electrons.

2. Place the atoms and draw a single bond.

Put C and O next to each other. A single bond uses 2 electrons.

Remaining electrons: 10−2=810 - 2 = 8.

3. Complete octets with lone pairs.

Give oxygen 3 lone pairs (6 electrons) to reach 8. Give carbon 1 lone pair (2 electrons) to reach 8.

Check: oxygen now has 22 (bond) + 66 (lone pairs) = 8. Carbon has 22 (bond) + 22 (lone pair) = 4. Carbon is short by 4 electrons.

Watch out

A common mistake is to stop here. Carbon only has 4 electrons in this structure — it violates the octet rule. CO is not stable as a single bond.

4. Form multiple bonds to fix carbon’s octet.

We need to give carbon 4 more electrons. The only way is to share more of oxygen’s lone pairs. Move one lone pair from oxygen into a bonding position — that makes a double bond. Now carbon has 6 electrons (still short). Move another lone pair from oxygen — that makes a triple bond. Now carbon has 8 electrons (2 from each of 3 bonds + 2 from its lone pair). Oxygen also has 8 (2 from each of 3 bonds + 2 from its lone pair).

5. Check the final structure.

The triple bond uses 6 electrons. Each atom has one lone pair (2 electrons each). Total used: 6+2+2=106 + 2 + 2 = 10 — matches our count.

Tip

The triple bond in CO is isoelectronic with the triple bond in N2_2 (both have 10 valence electrons). That’s why CO is so stable and has a very high bond dissociation energy.

6. Formal charges — a necessary check.

Formal charge = valence electrons − (lone pair electrons + ½ bonding electrons).

For carbon: 4−(2+½×6)=4−(2+3)=−14 - (2 + ½ \times 6) = 4 - (2 + 3) = -1.

For oxygen: 6−(2+½×6)=6−(2+3)=+16 - (2 + ½ \times 6) = 6 - (2 + 3) = +1.

So the structure has a negative formal charge on carbon and a positive formal charge on oxygen. This is unusual — normally the more electronegative atom (oxygen) should carry the negative charge. But in CO, the triple bond forces this charge distribution. It’s the best Lewis structure because it satisfies the octet rule for both atoms.

Important

The Lewis structure of CO is :C ⁣≡ ⁣O ⁣:\mathbf{:C\!\equiv\!O\!:} with a lone pair on each atom. The formal charges are −1\mathbf{-1} on C and +1\mathbf{+1} on O. This is the only structure that gives both atoms a complete octet.

The final Lewis dot structure

:C≡O:

Where each colon represents a lone pair (2 electrons), and the triple bond is three lines between C and O.

✓Final answer

The Lewis dot structure of CO is :C ⁣≡ ⁣O ⁣:\mathbf{:C\!\equiv\!O\!:}, with a triple bond between carbon and oxygen and one lone pair on each atom.

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