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Worked Examples · Example 7.16

Q.Fluorine exhibits only –1 oxidation state whereas other halogens exhibit +1, +3, +5 and +7 oxidation states also. Explain.

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Step 1 — Fluorine's unique atomic properties.

Fluorine has the smallest atomic radius and the highest electronegativity of all elements. Its valence shell is n=2n=2: only 2s2s and 2p2p orbitals exist — there is no 2d2d subshell.

Step 2 — Why F is restricted to –1.

Being the most electronegative element, fluorine has no atom that can pull electron density away from it, so it can never show a positive oxidation state — it always either gains an electron completely (F−F^-) or shares in a single covalent bond, effectively giving −1-1. With no valence dd orbitals to promote electrons into, it also cannot expand its octet to form multiple bonds.

Step 3 — Why other halogens show positive states. …

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