Q.One mole of acetone requires less heat to vapourise than 1 mol of water. Which of the two liquids has higher enthalpy of vapourisation?
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Start your 14-day free trial to unlock the full solution →The key idea is that enthalpy of vapourisation is the heat required to vaporise one mole of a substance. Since water needs more heat per mole than acetone, water has the higher enthalpy of vapourisation.
The question gives you a direct comparison: one mole of acetone needs less heat to turn into vapour than one mole of water. That’s the entire experimental fact. The enthalpy of vapourisation, , is defined as the heat absorbed when one mole of a liquid vaporises at constant pressure. So if water takes more heat per mole, its is larger.
Why does this difference exist? It comes down to intermolecular forces. Water molecules form strong hydrogen bonds with each other — each molecule can participate in up to four hydrogen bonds. Breaking those bonds to escape into the vapour phase requires a lot of energy. Acetone molecules have dipole-dipole interactions (and weaker hydrogen bonding via the carbonyl oxygen), but nothing as extensive as water’s network. So water’s is significantly higher.
Let’s walk through the reasoning step by step.
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Understand the definition. Enthalpy of vapourisation, , is the heat required to convert one mole of a liquid into vapour at constant pressure and temperature. It’s a molar quantity — always per mole.
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Interpret the given fact. The problem states: “One mole of acetone requires less heat to vapourise than 1 mol of water.” That is a direct statement about the molar heat of vapourisation. In symbols:
for one mole each.
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Connect heat to enthalpy. At constant pressure (which is the usual condition for boiling), the heat absorbed equals the change in enthalpy: . So the statement becomes:
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