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NCERT Exemplar · Q5

Q.Solve for xx: −5≤2−3x4≤9-5 \le \dfrac{2-3x}{4} \le 9.

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This is a compound linear inequality. Multiply all three parts by 4 (positive, so inequality signs stay the same), then isolate xx by subtracting 2 and dividing by -3 (which flips the inequality signs). The solution is −343≤x≤223-\frac{34}{3} \le x \le \frac{22}{3}.

The key idea here is that a compound inequality like a≤f(x)≤ba \le f(x) \le b is really two inequalities in one: a≤f(x)a \le f(x) and f(x)≤bf(x) \le b. We can work on all three parts simultaneously, as long as we apply the same operation to each part. The only operation that requires extra care is multiplication or division by a negative number — that flips the inequality signs.

Let’s walk through it.

  1. Start with the given inequality:

−5≤2−3x4≤9-5 \le \frac{2-3x}{4} \le 9

  1. Multiply all three parts by 4. Since 4 is positive, the inequality signs do not change direction:

−5×4≤2−3x≤9×4-5 \times 4 \le 2 - 3x \le 9 \times 4

which gives:

−20≤2−3x≤36-20 \le 2 - 3x \le 36

  1. Subtract 2 from all three parts. Subtracting a constant (2) does not affect the inequality direction:

−20−2≤−3x≤36−2-20 - 2 \le -3x \le 36 - 2

so:

−22≤−3x≤34-22 \le -3x \le 34

  1. Divide all three parts by -3. This is the critical step. Since we are dividing by a negative number, every inequality sign must be reversed:

−22−3≥x≥34−3\frac{-22}{-3} \ge x \ge \frac{34}{-3}

Simplifying the fractions:

223≥x≥−343\frac{22}{3} \ge x \ge -\frac{34}{3} …

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