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Q.The half plane represented by the inequality 2x+3y>62x + 3y > 6 does not contain any point of the

(a) first quadrant
(b) second quadrant
(c) third quadrant
(d) fourth quadrant
Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2022MCQ· 1mImportance★★★★★
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In the third quadrant both xx and yy are negative, so 2x+3y2x+3y is always negative there — it can never exceed 66, so the region 2x+3y>62x+3y>6 contains no third-quadrant point.

The line 2x+3y=62x+3y=6 has xx-intercept 33 (at (3,0)(3,0)) and yy-intercept 22 (at (0,2)(0,2)); the half-plane 2x+3y>62x+3y>6 lies on the side away from the origin (since at the origin 2(0)+3(0)=0<62(0)+3(0)=0<6).

In the third quadrant, x<0x<0 and y<0y<0, so 2x<02x<0 and 3y<03y<0, giving 2x+3y<02x+3y<0 for every point there. Since 0<60<6, certainly 2x+3y<62x+3y<6 throughout the third quadrant — it is impossible for 2x+3y>62x+3y>6 to hold.

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