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Q.Out of 100 students, two sections of 40 and 60 are formed. If you and your friend are among 100 students, then what is the probability that

(i) You both enter the same section ?
(ii) You both enter the different section ?
Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2020Subjective· 6mImportance★★★★★
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Treating placement as a random split, the chance both friends land in the same section works out to 17/3317/33, and in different sections to 16/3316/33.

Out of 100 students, 40 go into Section 1 and 60 go into Section 2 (a random partition). You and your friend are 2 of these 100 students.

  1. Probability both enter the same section. The first of the two friends can land in either section; the probability the second friend lands in the same section depends on how many spots of that type remain out of the 99 other students. P(both in Section 1 of 40)=40100×3999P(\text{both in Section 1 of 40}) = \dfrac{40}{100}\times\dfrac{39}{99} P(both in Section 2 of 60)=60100×5999P(\text{both in Section 2 of 60}) = \dfrac{60}{100}\times\dfrac{59}{99} Adding: P(same section)=40×39+60×59100×99=1560+35409900=51009900=1733P(\text{same section}) = \dfrac{40\times39 + 60\times59}{100\times99} = \dfrac{1560+3540}{9900} = \dfrac{5100}{9900} = \dfrac{17}{33}
  2. Probability both enter different sections. …

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