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Q.Out of 120 students, two sections of 50 and 70 are formed. If you and your friend are among the 120 students, find which is more likely to happen that you both enter the same section or different sections.

Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2021Subjective· 4mImportance★★★★★
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Both being placed in the section of 50, plus both being placed in the section of 70, gives P(same)=2651P(\text{same})=\frac{26}{51}, narrowly beating P(different)=2551P(\text{different})=\frac{25}{51}.

There are 120 students split into a section of 50 and a section of 70. Consider you and your friend among these 120.

Both in the 50-section: the probability the first of you is placed there is 50120\dfrac{50}{120}; given that, the probability the second is also placed there (49 spots left among 119 remaining students) is 49119\dfrac{49}{119}. So

P(both in 50)=50120×49119=245014280.P(\text{both in 50})=\dfrac{50}{120}\times\dfrac{49}{119}=\dfrac{2450}{14280}.

Both in the 70-section: similarly,

P(both in 70)=70120×69119=483014280.P(\text{both in 70})=\dfrac{70}{120}\times\dfrac{69}{119}=\dfrac{4830}{14280}.

Same section (either case):

P(same)=2450+483014280=728014280=2651≈0.5098.P(\text{same})=\dfrac{2450+4830}{14280}=\dfrac{7280}{14280}=\dfrac{26}{51}\approx0.5098.

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