Q. and . Define a relation from to by . Write in roster form.
The relation consists of all ordered pairs from where is an odd number. Checking each pair gives .
The core idea here is simple: we need to find every pair with from set and from set such that the difference is an odd integer. "Difference" here means subtraction — and we only care whether the result is odd, not whether it's positive or negative.
A quick intuition: an odd number is one that is not divisible by 2. When you subtract two integers, the parity (odd/even nature) of the result depends only on whether the two numbers have the same parity or different parity. If both are even or both are odd, their difference is even. If one is even and the other odd, their difference is odd. So we're really looking for pairs where and have opposite parity.
Let's check the parity of each element:
- : 1 (odd), 2 (even), 3 (odd), 5 (odd)
- : 4 (even), 6 (even), 9 (odd)
So the condition "difference is odd" means we pair an odd with an even , or an even with an odd .
Now let's list all possible pairs systematically.
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Take (odd). It must pair with an even from : and . Check: (odd), (odd). So and are in .
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Take (even). It must pair with an odd from : only . Check: (odd). So is in .
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Take (odd). Pair with even : and . Check: (odd), (odd). So and are in .
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Take (odd). Pair with even : and . Check: (odd), (odd). So and are in .
What about with or ? (even), (even) — not included. What about with ? (even), (even), (even) — not included.
A common mistake is to think "difference" means absolute difference. But the problem says "the difference between and " — in standard set theory and relations, this means , not . However, since parity of is the same as parity of (oddness doesn't depend on sign), the result would be the same either way here. Still, be precise.
So collecting all valid pairs, we get:
The relation in roster form is .
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