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Q.Find the equation of the line parellel to the line 3x−4y+2=03x - 4y + 2 = 0 and passing through the point (−2,3)(-2, 3).

Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2024Subjective· 2mImportance★★★★★
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The equation of the required line is 3x−4y+18=03x-4y+18=0.

Any line parallel to 3x−4y+2=03x-4y+2=0 has the form 3x−4y+k=03x-4y+k=0 for some constant kk (same coefficients of xx and yy, since parallel lines share the same slope).

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