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Q.If a, b, c are in A.P. then the straight line ax+by+c=0ax + by + c = 0 will always pass through

(a) (1,2)(1, 2)
(b) (−1,2)(-1, 2)
(c) (1,−2)(1, -2)
(d) (−1,−2)(-1, -2)
Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2025MCQ· 1mImportance★★★★★
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The A.P. condition 2b=a+c2b=a+c rearranges to a−2b+c=0a-2b+c=0, which says the line ax+by+c=0ax+by+c=0 passes through (1,−2)(1,-2) for every valid a,b,ca,b,c.

Since a,b,ca,b,c are in A.P., 2b=a+c2b = a+c, i.e.

a−2b+c=0.(∗)a - 2b + c = 0. \quad (\ast)

Substitute the candidate point (x,y)=(1,−2)(x,y)=(1,-2) into the line ax+by+c=0ax+by+c=0:

a(1)+b(−2)+c=a−2b+c.a(1) + b(-2) + c = a - 2b + c.

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