Q.Estimate the mean free path for a water molecule in water vapour at 373 K. Use information from Example 12.1 and Eq. (12.41) above (mean free path of an air molecule at STP, l=2.9×10−7 m).
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Kinetic Theory of Gases
Imagine you're sitting in a quiet room. The air around you feels still — but it isn't. Every second, billions of tiny particles (molecules of nitrogen, oxygen, and others) are zipping past you at hundreds of metres per second. They're constantly crashing into each other and into the walls, your skin, the furniture. You don't feel each individual hit because the molecules are so small and the collisions happen so fast. But collectively, those countless tiny impacts produce something you do feel: pressure.
That's the core intuition behind the kinetic theory of gases. It says: all the macroscopic properties of a gas — pressure, temperature, volume — can be explained by the motion of its molecules.
The Big Idea
Instead of treating a gas as a continuous, smooth substance (like a fluid), the kinetic theory treats it as a swarm of tiny, hard, perfectly elastic balls in constant, random motion. "Perfectly elastic" means that when two molecules collide, no kinetic energy is lost — they bounce off each other like ideal billiard balls, not like sticky clay.
From this simple picture, we can derive the gas laws (Boyle's, Charles's, Avogadro's) and even calculate things like the speed of sound in a gas.
The Five Assumptions (The Precise Statement)
For a gas to behave according to the kinetic theory in its simplest form, we make these assumptions:
-
A gas consists of a very large number of molecules.
The number is so huge that we can use statistics — individual molecules don't matter, only averages do.
-
The molecules are in constant, random motion.
They move in straight lines until they hit something (another molecule or a wall). There's no preferred direction.
-
The molecules are point masses.
Their actual size is negligible compared to the distance between them. In other words, the volume of the molecules themselves is tiny compared to the volume of the container.
-
Collisions are perfectly elastic.
No kinetic energy is lost when molecules collide with each other or with the walls. Total energy of the system stays constant.
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There are no intermolecular forces.
The molecules don't attract or repel each other except during collisions. Between collisions, they move freely.
These assumptions define an ideal gas. Real gases deviate from this behaviour at high pressure or low temperature, but the kinetic theory gives an excellent approximation for most everyday conditions.
How It Explains Pressure
Pressure is the force per unit area exerted by the gas on the walls of its container. In the kinetic picture:
- A molecule moving toward a wall hits it and bounces back.
- During the collision, the wall exerts a force on the molecule to reverse its momentum.
- By Newton's third law, the molecule exerts an equal and opposite force on the wall.
- Multiply that by the billions of collisions happening every second, and you get a steady, measurable pressure.
If you heat the gas, the molecules move faster. They hit the walls harder and more often — pressure increases. If you compress the gas into a smaller volume, molecules hit the walls more frequently — pressure increases again.
The Key Result: The Kinetic Equation
From these assumptions, we can derive a relationship between pressure P, volume V, and the average kinetic energy of the molecules. The result is:
PV=31Nmv2
Where:
- N = number of molecules
- m = mass of one molecule
- v2 = mean square speed of the molecules (average of the squares of their speeds)
Since the average kinetic energy of a molecule is K=21mv2, we can rewrite this as:
PV=32NK …
Concept: Molecular Volume Fraction — the mean free path scales inversely with the number density n of molecules. Since n∝P/T, we can compare the given air-at-STP value to water vapour at 373 K and 1 atm.
Step 1: At STP (273 K, 1 atm), air has lair=2.9×10−7 m. For water vapour at 373 K and 1 atm, the number density changes only with temperature (pressure same).
Step 2: Mean free path l∝1/n∝T (at constant P). So: …
The mean free path is l=1/(2nπd2) with n=P/kT. At fixed pressure l∝T, and taking the effective molecular size for water vapour as roughly that of air, scaling the given air value from 273 K to 373 K gives l≈4×10−7 m.
Reasoning
The mean free path depends on the number density n and the molecular diameter d:
l=2nπd21,n=kTP
At the same pressure, n∝1/T, so - treating the effective diameter of a water molecule as roughly the same as that of an air molecule (both a few angstrom, a fair estimate for an order-of-magnitude answer) - the mean free path scales directly with temperature:
lairlvapour=nvapournair=TairTvapour …
Rather than treating this as 'a different gas at a different condition,' notice only temperature is changing here (pressure stays at 1 atm), and l∝n−1∝T at fixed P (from PV=NkBT⇒n=P/kBT). That means you can scale the given air value directly by the temperature ratio, with no need to compute a molecular diameter or number density from scratch: $l_{water}=l_{air}\times(373/273)\approx4.0\times10 …
- Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2026Set ANNUAL1 markMCQQ.When the temperature of a gas is doubled (in Kelvin scale) while keeping its volume constant, the average speed of gas will –(a) Remain unchanged(b) Increase by a factor of 2(c) Increase by a factor of sqrt(2)(d) Decrease by a factor of sqrt(2)
›Reveal solutionSolution
Doubling the absolute temperature increases the average molecular speed by a factor of √2.
From kinetic theory, the rms speed of gas molecules is:
v_rms = √(3RT/M)
so v_rms ∝ √T (M and R are constants for a given gas).
If T is doubled (T → 2T), keeping volume constant (volume doesn't affect this relation anyway — it only depends on T and M):
…
- Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2023Set ANNUAL1 markQ.What is Mean free path?
›Reveal solutionSolution
Mean free path is the average distance a gas molecule travels freely before colliding with another molecule.
In a gas, molecules are in constant random motion and frequently collide with one another, changing direction and speed at each collision. Between two successive collisions, a molecule travels in a straight line for some distance, called its free path. Since different molecules (and even the same molecule between different pairs of collisions) travel different free path lengths, the average of all these free path lengths, taken over a large number of collisions, is called the mean free path, usually denoted λ.
…
- Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2022Set ANNUAL1 markQ.On what factors, does the average kinetic energy of gas molecules depend ?
›Reveal solutionSolution
The average kinetic energy of gas molecules depends only on the absolute temperature of the gas, not on its pressure, volume, or the type/mass of the gas.
From kinetic theory, the average translational kinetic energy per molecule of an ideal gas is:
KE=23kBT
where kB is Boltzmann's constant and T is the absolute temperature.
This relation shows that KE depends on only one variable: the absolute temperature T. It does not depend on:
- The pressure of the gas,
- The volume occupied by the gas, or
- The nature (identity/mass) of the gas molecules — a light gas like hydrogen and a heavy gas like oxygen have the same average kinetic energy per molecule at the same temperature (though their average speeds differ, since KE=21mv2 and m differs). …
- Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2020Set ANNUAL1 markQ.Find the ratio of root mean square speed of an ideal gas at 270 K and 30 K.
›Reveal solutionSolution
Since v_rms ∝ √T, the ratio of rms speeds at 270 K and 30 K is √(270/30) = √9 = 3.
From kinetic theory of gases, the root mean square speed of gas molecules is
vrms=M3RT
where R is the universal gas constant, T is the absolute temperature, and M is the molar mass of the gas. For a given gas, R and M are fixed, so
vrms∝T
…
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