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Q.A gas occupies a volume of 300 cc at 27°C and 620 mm pressure. The volume of gas at 47°C and 640 mm pressure is — (A) 260 cc
(B) 310 cc
(C) 390 cc
(D) 450 cc

Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2023MCQ· 1mImportance★★★★★
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Applying the combined gas law P₁V₁/T₁ = P₂V₂/T₂ to the given initial and final conditions gives a final volume of 310 cc.

Given: V1=300 ccV_1 = 300\ cc, T1=27∘C=300 KT_1 = 27^\circ C = 300\ K, P1=620 mmP_1 = 620\ mm (of Hg); T2=47∘C=320 KT_2 = 47^\circ C = 320\ K, P2=640 mmP_2 = 640\ mm (of Hg). Find V2V_2.

For a fixed amount of an ideal gas, the combined gas law states:

P1V1T1=P2V2T2\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

Rearranging for V2V_2:

V2=P1V1T2T1P2=620×300×320300×640V_2 = \frac{P_1V_1T_2}{T_1P_2} = \frac{620\times300\times320}{300\times640}

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