The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is (a) 663.821 (b) 664 (c) 6

NCERT Exemplar · Q2

Q. The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is

(a) 663.821

(b) 664

(d) 663.82

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Concept understanding — Significant Figures Calculation

Significant Figures: The Art of Honest Measurement

Imagine you're measuring the length of a table with a ruler that has marks every millimeter. You see the table edge falls somewhere between 152.3 cm and 152.4 cm. You estimate it as 152.35 cm. But here's the truth: you're certain about 152.3, pretty sure about the 0.05, and guessing about anything beyond that. Significant figures are simply a way to communicate how much of that number you actually know.

The Core Idea

Every measurement has uncertainty. Significant figures (or "sig figs") are the digits in a number that carry meaningful information about its precision. They include all the digits you're sure of, plus one more that you estimate.

Note

A digit is "significant" if removing it would change the precision of the measurement. Zeros can be tricky — they might just be placeholders.

The Rules (Memorize These)

1. Non-zero digits are always significant

$123.45$ has 5 sig figs. Simple.

2. Zeros between non-zero digits are significant

$1002$ has 4 sig figs. The zeros are "sandwiched" — they're part of the measurement.

3. Leading zeros are never significant

$0.00123$ has 3 sig figs. Those zeros just tell you where the decimal point is.

4. Trailing zeros are significant only if there's a decimal point

$1200$ has 2 sig figs (no decimal — zeros are placeholders)
$1200.$ has 4 sig figs (decimal tells us those zeros were measured)
$1200.0$ has 5 sig figs

5. Exact numbers have infinite sig figs

If you count 5 apples, that's exactly 5 — no uncertainty. Conversion factors like $1 \text{ m} = 100 \text{ cm}$ are exact by definition.

Tip

When in doubt, write the number in scientific notation. $1.20 \times 10^3$ clearly has 3 sig figs, while $1.2 \times 10^3$ has 2.

Why This Matters: Calculations

When you multiply or add measurements, the uncertainty propagates. You can't claim more precision than your least precise measurement.

Multiplication and Division

The result should have the same number of sig figs as the measurement with the fewest sig figs.

$3.14 \times 2.5 = 7.85$ but you report $7.9$ (2 sig figs, because 2.5 has only 2)

Addition and Subtraction

The result should have the same decimal places as the measurement with the fewest decimal places.

$12.11 + 18.0 = 30.11$ but you report $30.1$ (one decimal place, because 18.0 has one)

Watch out

These two rules are different! For multiplication, count sig figs. For addition, count decimal places. Mixing them up is the most common mistake.

A Concrete Example

You measure a rectangular field:

Length: $152.3$ m (4 sig figs)
Width: $45.0$ m (3 sig figs)

Area = $152.3 \times 45.0 = 6853.5$ m²

But your width measurement only has 3 sig figs, so you report $6.85 \times 10^3$ m² (or 6850 m², but that's ambiguous — use scientific notation).

The Big Picture

Significant figures aren't about being pedantic. They're about honesty in science. When you write $3.0$ instead of $3$ , you're telling the reader: "I measured this to the tenths place, and it was exactly 3.0 — not 2.9, not 3.1." That's valuable information.

Important

Final rule of thumb: Your answer cannot be more precise than your least precise measurement. Sig figs enforce that.

Queries such as "significant figures rules class 11 physics" and "significant figures calculation examples" are common around exam season, reflecting how central this topic is to the Units and Measurements chapter of the NCERT/CBSE Class 11 Physics curriculum. It's also a frequent source of numerical-based questions in JEE Main and NEET.

Why this formula?

Significant Figures: Why the Rules Work

Let’s start with the core idea: significant figures (sig figs) are a way to honestly report how precise a measurement is. The rules for addition/subtraction and multiplication/division aren’t arbitrary — they come directly from how uncertainty propagates through calculations.

1. The Fundamental Idea: Uncertainty is the Key

Every measurement has an uncertainty (error). When we say a length is 12.3 cm, we mean:

The true value lies somewhere between 12.25 cm and 12.35 cm (assuming ±0.05 cm uncertainty).
The last digit (3) is uncertain; the digits before it (1 and 2) are certain.

Why this matters: When we combine measurements, the uncertainty in the result depends on the uncertainties of the inputs. Sig fig rules are a shortcut for this uncertainty propagation.

2. Rule for Addition and Subtraction

Statement: The result should have the same number of decimal places as the measurement with the fewest decimal places.

Example:

$12.3 + 4.56 = 16.86$ → round to 16.9 (one decimal place, like 12.3)

Why this holds

Consider two measurements:

$A = 12.3 \pm 0.05$ (uncertainty in the tenths place)
$B = 4.56 \pm 0.005$ (uncertainty in the hundredths place)

When we add:

Certain digits: 12.3 has certainty up to the tenths place. 4.56 has certainty up to the hundredths place.
The weaker link: The tenths place of A is uncertain. So in the sum, the hundredths place (from B) is meaningless — because we don’t even know the tenths place of A exactly.

Mathematically, the absolute uncertainty in the sum is:

\Delta(A+B) = \sqrt{(\Delta A)^2 + (\Delta B)^2} \approx \sqrt{0.05^2 + 0.005^2} \approx 0.0502

This uncertainty is ~0.05, which affects the tenths place. So reporting the hundredths place is false precision.

Key takeaway: The result’s last significant digit is in the same decimal place as the least precise measurement’s last digit.

3. Rule for Multiplication and Division

Statement: The result should have the same number of significant figures as the measurement with the fewest significant figures.

Example:

$12.3 \times 4.56 = 56.088$ → round to 56.1 (three sig figs, like both inputs)

Why this holds

Let’s use relative uncertainty (percentage error):

$A = 12.3 \pm 0.05$ → relative uncertainty = $\frac{0.05}{12.3} \approx 0.00407$ (0.407%)
$B = 4.56 \pm 0.005$ → relative uncertainty = $\frac{0.005}{4.56} \approx 0.00110$ (0.110%)

For multiplication, relative uncertainties add (approximately):

\frac{\Delta(A \times B)}{A \times B} \approx \sqrt{\left(\frac{\Delta A}{A}\right)^2 + \left(\frac{\Delta B}{B}\right)^2}

Plugging in:

\approx \sqrt{0.00407^2 + 0.00110^2} \approx 0.00422 \text{ (0.422\%)}

Now, the absolute uncertainty in the product:

\Delta(A \times B) \approx 0.00422 \times (12.3 \times 4.56) \approx 0.00422 \times 56.088 \approx 0.237

This uncertainty (~0.2) affects the tenths place of the result. So the result 56.088 has uncertainty in the first decimal — meaning only three digits (5, 6, and the uncertain 1) are meaningful. That’s three sig figs, matching the input with fewer sig figs (both have three here).

Key takeaway: The number of sig figs in the result is limited by the least precise measurement’s number of sig figs, because relative uncertainty is dominated by the measurement with the largest relative error.

4. Why These Rules Are Different

Operation	Rule	Why different?
+ / −	Decimal places	Uncertainty is absolute — it depends on the position of the last digit
× / ÷	Sig figs	Uncertainty is relative — it depends on the fraction of the value

Example to see the difference:

$1000 + 0.001 = 1000$ (decimal places rule: 1000 has 0 decimal places, so result is 1000)
$1000 \times 0.001 = 1$ (sig figs rule: 1000 has 4 sig figs? Actually ambiguous — but if 1000 has 1 sig fig, result is $1 \times 10^0$ )

5. The Deeper Reason: It’s All About Honest Reporting

The rules exist because:

Measurements have inherent uncertainty — no measurement is exact.
Calculations propagate uncertainty — the result cannot be more precise than the least precise input.
Sig figs are a practical shortcut — they avoid doing full error propagation for every calculation, while still giving a reasonable estimate of precision.

Bottom line: The rules aren’t arbitrary — they’re derived from the mathematics of uncertainty. When you round to the correct number of sig figs, you’re saying: “This is how precisely I actually know the answer, given the precision of my measurements.”

Quick Exam Tip

Addition/Subtraction: Look at decimal places — the weakest link is the one with fewest decimals.
Multiplication/Division: Look at sig figs — the weakest link is the one with fewest sig figs.
Mixed operations: Follow order of operations, applying the appropriate rule at each step.

When adding numbers, the result must be rounded to the least precise decimal place among the terms. Here, 227.2 has only one decimal place, so the sum is rounded to one decimal place, giving 663.8.

The key idea is that in addition (or subtraction), the number of decimal places in the result is limited by the term with the fewest decimal places. This is because you cannot meaningfully report a digit in a place where one of the original numbers had no information — it would be a false precision.

Let’s break it down step by step.

Identify the decimal places in each term
- $436.32$ has two decimal places (hundredths).
- $227.2$ has one decimal place (tenths).
- $0.301$ has three decimal places (thousandths).
The least precise term is $227.2$ , with only one decimal place. This will determine the precision of the final answer.
Perform the addition exactly

436.32 + 227.2 + 0.301 = 663.821

This is the raw sum, but it contains digits (the hundredths and thousandths) that are not justified by the least precise term.

Round to the correct number of decimal places

Since the least precise term has one decimal place, the sum must be rounded to one decimal place. Look at the digit in the hundredths place (the second decimal): it is $2$ (from $663.82\underline{1}$ ). Since $2 < 5$ , we round down, keeping the tenths digit as $8$ .

So the rounded result is $663.8$ .

Watch out

A common mistake is to round the final answer to the least number of significant figures instead of the least number of decimal places. For addition, it’s always about decimal places, not significant figures. Here, $227.2$ has 4 significant figures, but that’s irrelevant — what matters is its one decimal place.

Check the options
- (A) 663.821 — too many decimal places (false precision).
- (B) 664 — rounded to the nearest whole number, which loses the tenths place unnecessarily.
- (C) 663.8 — correct: one decimal place, as required.
- (D) 663.82 — two decimal places, still too precise.

Tip

A quick mental check: imagine you measured lengths of $436.32$ m, $227.2$ m, and $0.301$ m. The $227.2$ m measurement is only accurate to the nearest tenth of a metre — you cannot know the hundredths place in the total, so the sum must stop at tenths.

✓Final answer

The correct option is (C) 663.8 .

Here’s a breakdown of the common mistakes students make on this significant figures in addition problem, and how to avoid each.

🧠 The Core Rule (Why it matters)

In addition and subtraction, the result is rounded to the least precise decimal place among the numbers — not the fewest total significant figures.

The numbers:

$436.32$ → 2 decimal places
$227.2$ → 1 decimal place
$0.301$ → 3 decimal places

The least precise is 1 decimal place (from $227.2$ ).

So the answer must be rounded to 1 decimal place.

✗ Mistake #1: Using the “fewest significant figures” rule (like in multiplication)

What students do:

They see $227.2$ has 4 significant figures, $0.301$ has 3, and think the answer should have 3 significant figures → they pick 664 (option B).

Why it’s wrong:

The “fewest significant figures” rule applies to multiplication/division, not addition/subtraction.

✓ How to avoid:

Always check the decimal places first for addition/subtraction.

Count digits after the decimal point in each number.
The answer’s last digit is in the same decimal place as the least precise number.

✗ Mistake #2: Reporting the raw sum without rounding

What students do:

They add:

$436.32 + 227.2 + 0.301 = 663.821$

and pick option A (663.821).

Why it’s wrong:

The sum is correct, but it ignores the precision rule. $227.2$ is only known to the tenths place, so the answer cannot have hundredths or thousandths.

✓ How to avoid:

After adding, immediately round to the least precise decimal place.

Here: $663.821$ rounded to 1 decimal place → 663.8.

✗ Mistake #3: Rounding to the wrong decimal place

What students do:

They know to round, but they round to 2 decimal places (because $436.32$ has 2) → they pick 663.82 (option D).

Why it’s wrong:

The least precise number is $227.2$ (1 decimal place), not $436.32$ .

You must round to the least number of decimal places among all terms.

✓ How to avoid:

List the decimal places: $436.32$ → 2 $227.2$ → 1 $0.301$ → 3
The smallest is 1.
Round the sum to 1 decimal place only.

✓ Correct Answer

663.8 → Option (C)

📌 Quick Checklist to Avoid These Mistakes

Step	Action
1	Add normally (ignore rounding for now)
2	Count decimal places in each number
3	Identify the smallest decimal place count
4	Round the sum to that decimal place
5	Never use “fewest significant figures” for addition/subtraction

Final tip: In exams, underline the number with the fewest decimal places before you start — that’s your rounding target.

Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.

Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2026Set ANNUAL1 markMCQ
$Q. A piece of paper is found to be 5.32 cm long and 2.4 cm broad. The area of the paper expressed with proper significant figures is -$
(a) 12.768 cm^2
(b) 12.76 cm^2
(c) 12.8 cm^2
(d) 13 cm^2
›Reveal solutionSolution
$5.32 \times 2.4 = 12.768$ , but rounded to the fewer significant figures of 2.4 (2 s.f.), the area is 13 cm².

Area $= \text{length} \times \text{breadth} = 5.32\ cm \times 2.4\ cm = 12.768\ cm^2$ .

Rule of significant figures in multiplication/division: the result must be reported with the same number of significant figures as the measurement with the fewest significant figures.

5.32 cm has 3 significant figures.

2.4 cm has only 2 significant figures.

So the answer must be rounded to 2 significant figures: $12.768 \to 13\ cm^2$ .

✓Final answer
$The correct option is (d) 13 cm² .$
Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2025Set ANNUAL1 markMCQ
$Q. The significant numbers of 4200 kg is$
(a) 2
(b) 4
(c) 3
(d) zero
›Reveal solutionSolution
Written as 4200 kg (no decimal point), only 4 and 2 count as significant digits — 2 significant figures.

The rule for significant figures on a number with trailing zeros and no decimal point is that those trailing zeros are NOT counted as significant, because we cannot tell from the way the number is written whether they were actually measured or are simply place-holding zeros needed to show the magnitude of the quantity.

For 4200 kg:

The non-zero digits 4 and 2 are always significant.

The two zeros after them, with no decimal point present, are ambiguous — by convention they are treated as not significant.

So 4200 kg has only 2 significant figures. (If the paper had instead written $4200. \text{ kg}$ or $4.200 \times 10^{3} \text{ kg}$ , all four digits would be significant — the way a number is expressed changes how many figures are treated as significant, even though the underlying quantity is the same.)

✓Final answer
$The correct option is (a) 2 significant figures — only the digits 4 and 2 in 4200 kg are significant.$
Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2025Set ANNUAL1 mark
$Q. What is meant by significant figures?$
›Reveal solutionSolution
Significant figures are the meaningful digits in a number that convey how precisely a quantity was measured.

When a quantity is measured using any instrument, the digits which are known reliably plus the one digit that is uncertain (estimated) are together called significant figures. For example, if a length is reported as 12.35 cm, the digits 1, 2, 3 are certain and the last digit 5 is uncertain (estimated), giving four significant figures in total.

Rules for counting significant figures:

All non-zero digits are significant (285 cm has 3 sig figs).

Zeros between two non-zero digits are significant (2.005 has 4 sig figs).

Leading zeros (before the first non-zero digit) are NOT significant (0.03 has 1 sig fig).

Trailing zeros after a decimal point ARE significant (0.200 has 3 sig figs).

Trailing zeros in a number without a decimal point may or may not be significant, and are best expressed in scientific notation to avoid ambiguity.

Significant figures matter because the result of any calculation involving measured quantities cannot be more precise than the least precise measurement used, so tracking significant figures ensures the reported precision of a result is honest.

✓Final answer
$Significant figures are all the digits in a measured or calculated quantity that are known with certainty plus one additional uncertain (estimated) digit — they show the precision of a measurement.$
Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2024Set ANNUAL1 markMCQ
$Q. The number of significant figures in the scientific notation 1.23 \times 10^5 is -$
(a) One
(b) Three
(c) Five
(d) Eight
›Reveal solutionSolution

Counting the digits in the coefficient 1.23 (the power of 10 is not counted) gives three significant figures.

In scientific notation $N \times 10^n$ , the exponent 10^n merely fixes the decimal place/order of magnitude and carries no information about precision. Only the digits in the coefficient N are significant.

Here N = 1.23, which has exactly three digits: 1, 2, and 3 — all of them significant since they're all non-zero digits explicitly written.

✓Final answer
$The correct option is (b) Three.$
Council of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2021Set ANNUAL1 mark
$Q. What is the precision of measurement?$
›Reveal solutionSolution
Precision measures how close repeated readings of the same quantity are to each other, regardless of whether they are close to the true value.

In any experimental measurement, two related but distinct ideas describe reliability:

Accuracy: how close a measured value is to the true/accepted value.

Precision: how close repeated measurements of the same quantity are to one another (i.e., how reproducible the readings are).

A set of measurements can be precise (tightly clustered) but not accurate (clustered far from the true value, indicating a systematic error), or accurate but not precise, or both, or neither. Precision is purely about the spread/agreement among the repeated readings themselves.

✓Final answer
$Precision is the degree of agreement (closeness) among a set of repeated measurements of the same quantity — it reflects reproducibility, not necessarily correctness (accuracy).$

←Previous questionQ1 — The number of significant figures in 0.06900 is (a) 5 (b) 4 (c) 2 (d) …→Next questionQ3 — The mass and volume of a body are 4.237 g and 2.5 cm³, respectively. T…

Q.The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is

Concept understanding — Significant Figures Calculation

Significant Figures: The Art of Honest Measurement

The Core Idea

The Rules (Memorize These)

1. Non-zero digits are always significant

2. Zeros between non-zero digits are significant

3. Leading zeros are never significant

4. Trailing zeros are significant only if there's a decimal point

5. Exact numbers have infinite sig figs

Why This Matters: Calculations

Multiplication and Division

Addition and Subtraction

A Concrete Example

The Big Picture

Why this formula?

Significant Figures: Why the Rules Work

1. The Fundamental Idea: Uncertainty is the Key

2. Rule for Addition and Subtraction

Why this holds

3. Rule for Multiplication and Division

Why this holds

4. Why These Rules Are Different

5. The Deeper Reason: It’s All About Honest Reporting

Quick Exam Tip

Method: Addition with Significant Figures (Decimal Place Rule)

Steps

Final Answer

🧠 The Core Rule (Why it matters)

✗ Mistake #1: Using the “fewest significant figures” rule (like in multiplication)

✗ Mistake #2: Reporting the raw sum without rounding

✗ Mistake #3: Rounding to the wrong decimal place

✓ Correct Answer

📌 Quick Checklist to Avoid These Mistakes

Q.The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is

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