Q.State the principal of conservation of mechanical energy. Prove the principle of conservation of mechanical energy in the case of a freely falling body. (1+4=5) OR What is an elastic collision ? Obtain the expression for velocities after collision when two bodies undergo perfectly elastic collision in one dimension. (1+4=5)
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →The total mechanical energy (KE + PE) of a system stays constant under conservative forces alone; for a body falling freely from height , KE + PE = at every point of the fall, proving the principle.
Statement: In the absence of non-conservative (dissipative) forces such as friction or air resistance, the total mechanical energy of a system — the sum of its kinetic energy (KE) and potential energy (PE) — remains constant throughout its motion, even though KE and PE may individually change (converting into each other).
Proof for a freely falling body:
Consider a body of mass released from rest from a height above the ground (point A). Let it fall freely (only gravity acting, air resistance neglected) and consider an intermediate point B at height above the ground, and the ground itself as point C.
At point A (top, start of fall):
- Height above ground = , speed
At point B (height , having fallen a distance ):
Using (from , ):
At point C (ground, height = 0):
Using :
- …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.