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Q.A DNA segment has a total of 1000 nucleotides, out of which 240 of them are adenine containing nucleotides. How many pyrimidine bases this DNA segment possesses? OR If the gene frequency of a recessive allele t is 0.2, find out the percentage of individuals with genotype TT, Tt and tt in the population.

Manipur CohsemCOHSEM Manipur Higher Secondary Board 2024Subjective· 3mImportance★★★★★
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Using Chargaff's rule (A = T, G = C) on a 1000-nucleotide double-stranded DNA segment with 240 adenine bases gives 500 pyrimidine bases (240 T + 260 C).

Part (i) — Pyrimidine count:

In double-stranded DNA, Chargaff's rule states that Adenine (A) = Thymine (T), and Guanine (G) = Cytosine (C), because A pairs with T via 2 hydrogen bonds and G pairs with C via 3 hydrogen bonds.

Given: total nucleotides = 1000; Adenine (A) = 240.

Since A = T, Thymine (T) = 240.

So A + T = 240 + 240 = 480.

Remaining bases, G + C = 1000 − 480 = 520.

Since G = C, Guanine (G) = Cytosine (C) = 260 each.

Pyrimidine bases are Cytosine and Thymine (purines are Adenine and Guanine).

Pyrimidines = T + C = 240 + 260 = 500.

Part (ii) — OR: Hardy–Weinberg genotype percentages: …

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