Skip to content
Question of 104

Q.Check if the relation RR in the set R\mathbf{R} of real numbers defined as R={(a,b):a<b}R=\{(a,b):a<b\} is

(i) Symmetric and
(ii) Transitive.
Manipur CohsemCOHSEM Manipur Higher Secondary Board 2026Subjective· 2mImportance★★★★★
0% · 0/104 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

a<ba<b does not give b<ab<a (not symmetric); but a<ba<b and b<cb<c give a<ca<c (transitive).

(i) Symmetric? Take (a,b)∈R(a,b)\in R, i.e. a<ba<b. For symmetry we would need b<ab<a as well. But e.g. (1,2)∈R(1,2)\in R since 1<21<2, while (2,1)∉R(2,1)\notin R since 2≮12\not<1. So RR is not symmetric.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.