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Q.Prove that the relation R defined by R={(a,b):a≤b}R = \{(a, b) : a \le b\} on the set R of real numbers is reflexive and transitive but not symmetric.

Rajasthan RbseRajasthan Board Senior Secondary Examination 2026Subjective· 2mImportance★★★★★
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Check each property directly from the definition a R b  ⟺  a≤ba\,R\,b \iff a\le b.

Reflexive: For every a∈Ra\in\mathbb R, a≤aa\le a is true, so (a,a)∈R(a,a)\in R for all aa. Hence R is reflexive.

Transitive: If (a,b)∈R(a,b)\in R and (b,c)∈R(b,c)\in R, i.e. a≤ba\le b and b≤cb\le c, then a≤ca\le c, so (a,c)∈R(a,c)\in R. Hence R is transitive.

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