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Q.A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20A in 0.5s, what is the change of flux linkage with the other coil?

Manipur CohsemCOHSEM Manipur Higher Secondary Board 2022Subjective· 3mImportance★★★★★
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ΔΦ2=M ΔI1=1.5 H×20 A=30\Delta\Phi_2 = M\,\Delta I_1 = 1.5\text{ H} \times 20\text{ A} = 30 Wb.

For two magnetically coupled coils with mutual inductance MM, the flux linked with coil 2 due to the current I1I_1 in coil 1 is Φ2=MI1\Phi_2 = MI_1. The change in flux linkage as I1I_1 changes is therefore

ΔΦ2=M ΔI1=1.5 H×(20−0) A=30 Wb\Delta\Phi_2 = M\,\Delta I_1 = 1.5\ \text{H} \times (20 - 0)\ \text{A} = 30\ \text{Wb}

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