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Q.Homolytic fission of a covalent bond leads to the formation of

(a) Electrophile
(b) Nucleophile
(c) Free radical
(d) Carbocation
Meghalaya MboseMBOSE Meghalaya 11th Board 2020MCQ· 1mImportance★★★★★
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Homolytic (symmetrical) fission of a covalent bond gives two neutral species each with an unpaired electron — free radicals.

A covalent bond A-B is formed by a shared pair of electrons. It can break in two ways:

  • Homolytic fission: the bond breaks symmetrically, and each atom takes exactly one electron of the shared pair, i.e., A-B → A• + B•. Each product is a neutral species with one unpaired electron, called a free radical. This typically requires energy input such as heat, light (UV), or peroxides, and occurs in non-polar/gas-phase or radical-chain reactions.
  • Heterolytic fission (for contrast): the bond breaks unsymmetrically, and both electrons go to one atom, giving a cation and an anion (e.g. a carbocation/electrophile and a carbanion/nucleophile). …

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